// setup: Brent's new algorithm
    // we are interested in two things: distance of a test point from
    // the ideal 'line', and the distance of a test point from two
    // actual points, one in the 'correct' direction and one in the
    // 'incorrect' direction.
    // scale distance by 10 for more interesting numbers.
    int l,m;        // for line equation lx + my = 0
    l = (x - you.x_pos);
    m = (you.y_pos - y);
    int tx, ty;         // test x,y
    int rx, ry;         // x,y relative to you.
    int sx, sy;         // test point in the correct direction
    int bx = x;         // best x
    int by = y;         // best y

    int best_dist = 10000;
    sx = l;
    sy = -m;
    // for each point (a,b), distance from the line is | la + mb |
    for(int tries = pow * pow / 500 + 1; tries > 0; tries--)

    const int dist = random2(6) + 2;  // 2-7
    const int ox = you.x_pos + (x - you.x_pos) * dist;
    const int oy = you.y_pos + (y - you.y_pos) * dist;
   
    int tx, ty;
    for ( int i = 0; i < (pow*pow) / 500 + 1; ++i )

        if (!random_near_space(you.x_pos, you.y_pos, tx, ty))

        // find a space near our target...
        if ( !random_near_space(ox, oy, tx, ty) )

        rx = tx - you.x_pos;
        ry = ty - you.y_pos;
        int dist = l * rx + m * ry;
        dist *= 10 * dist;      // square and multiply by 10
        // check distance to test points
        int dist1 = distance(rx, ry, sx, sy) * 10;
        int dist2 = distance(rx, ry, -sx, -sy) * 10;
        // 'good' points will always be closer to test point 1
        if (dist2 < dist1)
            dist += 80;          // make the point less attractive
        if (dist < best_dist)
        {
            best_dist = dist;
            bx = tx;
            by = ty;
        }

        
        // which is close enough, and also far enough from us
        if ( distance(ox, oy, tx, ty) <= 10 &&
             distance(you.x_pos, you.y_pos, tx, ty) >= 8 )
            break;

    you.x_pos = bx;
    you.y_pos = by;

    return (1);

    you.x_pos = tx;
    you.y_pos = ty;
    return 1;