; REQUIRES: asserts ; RUN: opt -mtriple=s390x-unknown-linux -mcpu=z13 -loop-vectorize \ ; RUN: -debug-only=loop-vectorize,vectorutils -max-interleave-group-factor=64\ ; RUN: -disable-output < %s 2>&1 | FileCheck %s ; ; Check that some cost estimations for interleave groups make sense. ; This loop is loading four i16 values at indices [0, 1, 2, 3], with a stride ; of 4. At VF=4, memory interleaving means loading 4 * 4 * 16 bits = 2 vector ; registers. Each of the 4 vector values must then be constructed from the ; two vector registers using one vperm each, which gives a cost of 2 + 4 = 6. ; ; CHECK: LV: Checking a loop in 'fun0' ; CHECK: LV: Found an estimated cost of 6 for VF 4 For instruction: %ld0 = load i16 ; CHECK: LV: Found an estimated cost of 0 for VF 4 For instruction: %ld1 = load i16 ; CHECK: LV: Found an estimated cost of 0 for VF 4 For instruction: %ld2 = load i16 ; CHECK: LV: Found an estimated cost of 0 for VF 4 For instruction: %ld3 = load i16 define void @fun0(i16 *%ptr, i16 *%dst) { entry: br label %for.body for.body: %ivptr = phi i16* [ %ptr.next, %for.body ], [ %ptr, %entry ] %iv = phi i64 [ %inc, %for.body ], [ 0, %entry ] %inc = add i64 %iv, 4 %ptr0 = getelementptr inbounds i16, i16* %ivptr, i64 0 %ld0 = load i16, i16* %ptr0 %ptr1 = getelementptr inbounds i16, i16* %ivptr, i64 1 %ld1 = load i16, i16* %ptr1 %ptr2 = getelementptr inbounds i16, i16* %ivptr, i64 2 %ld2 = load i16, i16* %ptr2 %ptr3 = getelementptr inbounds i16, i16* %ivptr, i64 3 %ld3 = load i16, i16* %ptr3 %a1 = add i16 %ld0, %ld1 %a2 = add i16 %a1, %ld2 %a3 = add i16 %a2, %ld3 %dstptr = getelementptr inbounds i16, i16* %dst, i64 %iv store i16 %a3, i16* %dstptr %ptr.next = getelementptr inbounds i16, i16* %ivptr, i64 4 %cmp = icmp eq i64 %inc, 100 br i1 %cmp, label %for.end, label %for.body for.end: ret void } ; This loop loads one i8 value in a stride of 3. At VF=16, this means loading ; 3 vector registers, and then constructing the vector value with two vperms, ; which gives a cost of 5. ; ; CHECK: LV: Checking a loop in 'fun1' ; CHECK: LV: Found an estimated cost of 5 for VF 16 For instruction: %ld0 = load i8 define void @fun1(i8 *%ptr, i8 *%dst) { entry: br label %for.body for.body: %ivptr = phi i8* [ %ptr.next, %for.body ], [ %ptr, %entry ] %iv = phi i64 [ %inc, %for.body ], [ 0, %entry ] %inc = add i64 %iv, 4 %ptr0 = getelementptr inbounds i8, i8* %ivptr, i64 0 %ld0 = load i8, i8* %ptr0 %dstptr = getelementptr inbounds i8, i8* %dst, i64 %iv store i8 %ld0, i8* %dstptr %ptr.next = getelementptr inbounds i8, i8* %ivptr, i64 3 %cmp = icmp eq i64 %inc, 100 br i1 %cmp, label %for.end, label %for.body for.end: ret void } ; This loop is loading 4 i8 values at indexes [0, 1, 2, 3], with a stride of ; 32. At VF=2, this means loading 2 vector registers, and using 4 vperms to ; produce the vector values, which gives a cost of 6. ; ; CHECK: LV: Checking a loop in 'fun2' ; CHECK: LV: Found an estimated cost of 6 for VF 2 For instruction: %ld0 = load i8 ; CHECK: LV: Found an estimated cost of 0 for VF 2 For instruction: %ld1 = load i8 ; CHECK: LV: Found an estimated cost of 0 for VF 2 For instruction: %ld2 = load i8 ; CHECK: LV: Found an estimated cost of 0 for VF 2 For instruction: %ld3 = load i8 define void @fun2(i8 *%ptr, i8 *%dst) { entry: br label %for.body for.body: %ivptr = phi i8* [ %ptr.next, %for.body ], [ %ptr, %entry ] %iv = phi i64 [ %inc, %for.body ], [ 0, %entry ] %inc = add i64 %iv, 4 %ptr0 = getelementptr inbounds i8, i8* %ivptr, i64 0 %ld0 = load i8, i8* %ptr0 %ptr1 = getelementptr inbounds i8, i8* %ivptr, i64 1 %ld1 = load i8, i8* %ptr1 %ptr2 = getelementptr inbounds i8, i8* %ivptr, i64 2 %ld2 = load i8, i8* %ptr2 %ptr3 = getelementptr inbounds i8, i8* %ivptr, i64 3 %ld3 = load i8, i8* %ptr3 %a1 = add i8 %ld0, %ld1 %a2 = add i8 %a1, %ld2 %a3 = add i8 %a2, %ld3 %dstptr = getelementptr inbounds i8, i8* %dst, i64 %iv store i8 %a3, i8* %dstptr %ptr.next = getelementptr inbounds i8, i8* %ivptr, i64 32 %cmp = icmp eq i64 %inc, 100 br i1 %cmp, label %for.end, label %for.body for.end: ret void } ; This loop is loading 4 i8 values at indexes [0, 1, 2, 3], with a stride of ; 30. At VF=2, this means loading 3 vector registers, and using 4 vperms to ; produce the vector values, which gives a cost of 7. This is the same loop ; as in fun2, except the stride makes the second iterations values overlap a ; vector register boundary. ; ; CHECK: LV: Checking a loop in 'fun3' ; CHECK: LV: Found an estimated cost of 7 for VF 2 For instruction: %ld0 = load i8 ; CHECK: LV: Found an estimated cost of 0 for VF 2 For instruction: %ld1 = load i8 ; CHECK: LV: Found an estimated cost of 0 for VF 2 For instruction: %ld2 = load i8 ; CHECK: LV: Found an estimated cost of 0 for VF 2 For instruction: %ld3 = load i8 define void @fun3(i8 *%ptr, i8 *%dst) { entry: br label %for.body for.body: %ivptr = phi i8* [ %ptr.next, %for.body ], [ %ptr, %entry ] %iv = phi i64 [ %inc, %for.body ], [ 0, %entry ] %inc = add i64 %iv, 4 %ptr0 = getelementptr inbounds i8, i8* %ivptr, i64 0 %ld0 = load i8, i8* %ptr0 %ptr1 = getelementptr inbounds i8, i8* %ivptr, i64 1 %ld1 = load i8, i8* %ptr1 %ptr2 = getelementptr inbounds i8, i8* %ivptr, i64 2 %ld2 = load i8, i8* %ptr2 %ptr3 = getelementptr inbounds i8, i8* %ivptr, i64 3 %ld3 = load i8, i8* %ptr3 %a1 = add i8 %ld0, %ld1 %a2 = add i8 %a1, %ld2 %a3 = add i8 %a2, %ld3 %dstptr = getelementptr inbounds i8, i8* %dst, i64 %iv store i8 %a3, i8* %dstptr %ptr.next = getelementptr inbounds i8, i8* %ivptr, i64 30 %cmp = icmp eq i64 %inc, 100 br i1 %cmp, label %for.end, label %for.body for.end: ret void }